6m^2=13+28

Solution for 6m^2=13+28 equation:

6m^2=13+28

We move all terms to the left:

6m^2-(13+28)=0

We add all the numbers together, and all the variables

6m^2-41=0

a = 6; b = 0; c = -41;
Δ = b2-4ac
Δ = 02-4·6·(-41)
Δ = 984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{984}=\sqrt{4*246}=\sqrt{4}*\sqrt{246}=2\sqrt{246}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{246}}{2*6}=\frac{0-2\sqrt{246}}{12}
=-\frac{2\sqrt{246}}{12}
=-\frac{\sqrt{246}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{246}}{2*6}=\frac{0+2\sqrt{246}}{12}
=\frac{2\sqrt{246}}{12}
=\frac{\sqrt{246}}{6}
$